亚洲男人天堂av,国产一区二区久久精品,国产精品一区二区久久精品,国产精品久久久久久一区二区三区,五月婷婷在线观看视频,亚洲狠狠色丁香婷婷综合

歡迎您訪問數學考題練習:一批救災物資分別隨16列貨車從甲站緊急調運到三!

數學考題練習:一批救災物資分別隨16列貨車從甲站緊急調運到三

更新時間:2024-01-12 14:07:18作者:貝語網校

一批救災物資分別隨16列貨車從甲站緊急調運到三百多里以外的乙站,已知每列貨車的平均速度都相等,且記為v公里/小時.兩列貨車實在運行中的間隔不小于公里,這批救災物資全部運到目的地最快需要6小時,那么每隔________分鐘從甲站向乙站發一趟貨車才能使這批貨物在6小時內運到.

試題答案

12

試題解析

設每隔x分鐘從甲站向乙站發一趟貨車才能使這批貨物在6小時內運到,要想節省時間就要讓第1列貨車到達乙站時,第16列貨車剛從甲站出發,兩列車在運行中的間隔等于公里,即根據題意可列方程2××15=6,解方程即可.

解答:設每隔x分鐘從甲站向乙站發一趟貨車才能使這批貨物在6小時內運到,根據題意如圖所示:

要想節省時間就要讓第1列貨車到達乙站時,第16列貨車剛從甲站出發,兩列車在運行中的間隔等于公里,

根據題意得:

2××15=6,

解得:x=12(分鐘).

故答案填:12.

點評:本題考查了一元一次方程的應用.本題敘述較長,解題關鍵是要讀懂題意,根據題目給出的條件,找出合適的等量關系列出方程,再求解.

主站蜘蛛池模板: | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | |