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歡迎您訪問雞兔同籠評課:雞兔同籠問題解析及方法{寫出來方法}(人教版6年級上冊數學書)!

雞兔同籠評課:雞兔同籠問題解析及方法{寫出來方法}(人教版6年級上冊數學書)

更新時間:2021-06-13 00:07:57作者:admin2

16×6表示想成全錯應該是倒扣96分 , 現在是得了16分,他們的差距是112分, 然后除以16道題 = 7道是對的 也可以是想成全對的先:16×10 = 160分,應該有160分的 現在每改成一道錯的就會少16分, 160÷16 = 有10個16分,我們只要留一個16分 就可以了,所以算式也可以16×10÷16-1 = 9道錯的

雞兔同籠問題有沒有典型例題?

例題1、有若干只雞兔同在一個籠子里,從上面數,有35個頭,從下面數,有94只腳。問籠中有幾只雞?()
A?? 12
B?? 19
C?? 23
D?? 24

講解雞兔同籠評課:雞兔同籠問題的經典例題,我們結合假設法跟公式解題。假設全部是雞的話,比實際少算了腳數,因此有:總量之差是實際的總腳數94,減去,假設下的總腳數35*2=70,又知每只兔子比雞多2只,因此,兔子的數量是:24/2=12,答案A。這題比較簡單,但隨著公務員考試的競爭力越來越大,我們知道考題也越來越多樣化,不過,基本知識點還是不會變,只是出題的形式會有變動。

數學雞兔同籠問題

一元一次方程就可以的:

設有自行車x輛,則根據題意,三輪車有(10-x)輛

因為自行車每輛2個輪子,三輪車每輛三個輪子,所以:

2x+3(10-x)=26

解得x=4

所以自行車4輛,三輪車6輛

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